x^2-5x+28=0

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Solution for x^2-5x+28=0 equation:


Simplifying
x2 + -5x + 28 = 0

Reorder the terms:
28 + -5x + x2 = 0

Solving
28 + -5x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + -5x + -28 + x2 = 0 + -28

Reorder the terms:
28 + -28 + -5x + x2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + -5x + x2 = 0 + -28
-5x + x2 = 0 + -28

Combine like terms: 0 + -28 = -28
-5x + x2 = -28

The x term is -5x.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5x + 6.25 + x2 = -28 + 6.25

Reorder the terms:
6.25 + -5x + x2 = -28 + 6.25

Combine like terms: -28 + 6.25 = -21.75
6.25 + -5x + x2 = -21.75

Factor a perfect square on the left side:
(x + -2.5)(x + -2.5) = -21.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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